10. EMF of a cell from a lead anode in a 2.0 * 10-3 M KBr solution with pH 8.00 saturated with PbOHBr, and SVE is 0.303 V. Schematically draw the cell and calculate Ks PbOHBr. Answer: 2.0*10-15
If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.