In two reactions of the same order, the difference in activation energies is E2 - E1 = 40 kJ/mol. At a temperature of 293 K, the ratio of the rate constants is equal to k1/k2 = 2. At what temperature will the rate constants become equal?
If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.
No feedback yet