106. Solving a chemistry problem

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623. Standard electrode potentials are known at 25 °C
Pb2 (aq) 2e = Pb(t)
PbSO4(t) 2e = Pb(t) SO42-(aq)

Find the Gibbs energy and the water solubility product PbSO4(m) = Pb2(aq)SO42-(aq).

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