111. Solving a chemistry problem

K V 100 ml 0.05 n. M (NO3) 2 (f´eq = 1\2) was added m 10 g of the cation exchanger in the H-form. After equilibrium was established, the concentration decreased to C=0.006 mol-eq/l. Determine the static exchange capacity (mmol / g) of the cation exchanger, taking the molar mass of the equivalent of M (1/2 Zn2)