The reaction С6Н6(g) = 3С2Н2(g) is given.
Calculate the standard Gibbs energy of the reaction at temperatures of 25°C and 750°C. For each temperature, draw a conclusion about the possibility of a spontaneous reaction. Determine the temperature range of spontaneous reaction.
If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.
No feedback yet