Glinka Problem 296
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296. Calculate ΔH°298 formation of MgCO3(k.) at 298 K, using the following data:
C(graphite)+O2(g)=CO2(g); ΔH°298=-393.5 kJ
2Mg(c.)+O2=2MgO(c.); ΔH°298=-1203.6 kJ
MgO(c.)+CO2(g.)=MgCO3(c.); ΔH°298=-117.7 kJ
C(graphite)+O2(g)=CO2(g); ΔH°298=-393.5 kJ
2Mg(c.)+O2=2MgO(c.); ΔH°298=-1203.6 kJ
MgO(c.)+CO2(g.)=MgCO3(c.); ΔH°298=-117.7 kJ
Read the product description. After payment, the system will redirect you to a page with a ready-made solution to problem 296 from the collection: Glinka N.L. Problems and exercises in general chemistry. Textbook for universities / Ed. V.A. Rabinovich and Kh.M. Rubina. – 23rd ed., revised. – L.: Chemistry, 1985. – 264 p., ill. The solution is a document formatted in MS Word.
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