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In the experiment with Fresnel mirrors the distance d between the virtual image of the light source is 0.5 mm, the distance l from them to the screen is 3 m. The wavelength of 0.6 microns. Interference fringes to determine the width on the screen.
Detailed solution with a short recording conditions, laws and formulas used in the decision, the withdrawal of the calculation formula and the answer.
If you have any questions about the decision to write. I try to help.
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